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3331011221981 is a prime number
BaseRepresentation
bin110000011110001111101…
…111011001100111011101
3102210102220220021121100022
4300132033233121213131
5414033402333100411
611030125002441525
7462441364135352
oct60361757314735
912712826247308
103331011221981
111074745aa5053
124596a4b032a5
131b216138c8b1
14b73168b2629
155b9a96c7edb
hex3078fbd99dd

3331011221981 has 2 divisors, whose sum is σ = 3331011221982. Its totient is φ = 3331011221980.

The previous prime is 3331011221953. The next prime is 3331011222023. The reversal of 3331011221981 is 1891221101333.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3050031716356 + 280979505625 = 1746434^2 + 530075^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3331011221981 is a prime.

It is a super-2 number, since 2×33310112219812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3331011221281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665505610990 + 1665505610991.

It is an arithmetic number, because the mean of its divisors is an integer number (1665505610991).

Almost surely, 23331011221981 is an apocalyptic number.

It is an amenable number.

3331011221981 is a deficient number, since it is larger than the sum of its proper divisors (1).

3331011221981 is an equidigital number, since it uses as much as digits as its factorization.

3331011221981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 35.

The spelling of 3331011221981 in words is "three trillion, three hundred thirty-one billion, eleven million, two hundred twenty-one thousand, nine hundred eighty-one".