Base | Representation |
---|---|
bin | 11111000001011100… |
… | …011110110100010101 |
3 | 10011222110002112000101 |
4 | 133001130132310111 |
5 | 1021204410140041 |
6 | 23145202014101 |
7 | 2256313240252 |
oct | 370134366425 |
9 | 104873075011 |
10 | 33310240021 |
11 | 13143842393 |
12 | 6557647331 |
13 | 31ab1212c6 |
14 | 187dd2c429 |
15 | cee550b31 |
hex | 7c171ed15 |
33310240021 has 2 divisors, whose sum is σ = 33310240022. Its totient is φ = 33310240020.
The previous prime is 33310239997. The next prime is 33310240031. The reversal of 33310240021 is 12004201333.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30132099396 + 3178140625 = 173586^2 + 56375^2 .
It is a cyclic number.
It is not a de Polignac number, because 33310240021 - 211 = 33310237973 is a prime.
It is a super-2 number, since 2×333102400212 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33310240031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16655120010 + 16655120011.
It is an arithmetic number, because the mean of its divisors is an integer number (16655120011).
Almost surely, 233310240021 is an apocalyptic number.
It is an amenable number.
33310240021 is a deficient number, since it is larger than the sum of its proper divisors (1).
33310240021 is an equidigital number, since it uses as much as digits as its factorization.
33310240021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 33310240021 its reverse (12004201333), we get a palindrome (45314441354).
The spelling of 33310240021 in words is "thirty-three billion, three hundred ten million, two hundred forty thousand, twenty-one".
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