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3331123020053 is a prime number
BaseRepresentation
bin110000011110010110011…
…001111000000100010101
3102210110012200122112110122
4300132112121320010111
5414034114443120203
611030144035001325
7462444222326303
oct60362631700425
912713180575418
103331123020053
1110747a3114654
12459716439245
131b217b5a44ba
14b7327695273
155b9b440d538
hex30796678115

3331123020053 has 2 divisors, whose sum is σ = 3331123020054. Its totient is φ = 3331123020052.

The previous prime is 3331123020037. The next prime is 3331123020059. The reversal of 3331123020053 is 3500203211333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3099437712484 + 231685307569 = 1760522^2 + 481337^2 .

It is a cyclic number.

It is not a de Polignac number, because 3331123020053 - 24 = 3331123020037 is a prime.

It is a super-2 number, since 2×33311230200532 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3331123020059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665561510026 + 1665561510027.

It is an arithmetic number, because the mean of its divisors is an integer number (1665561510027).

Almost surely, 23331123020053 is an apocalyptic number.

It is an amenable number.

3331123020053 is a deficient number, since it is larger than the sum of its proper divisors (1).

3331123020053 is an equidigital number, since it uses as much as digits as its factorization.

3331123020053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4860, while the sum is 26.

Adding to 3331123020053 its reverse (3500203211333), we get a palindrome (6831326231386).

The spelling of 3331123020053 in words is "three trillion, three hundred thirty-one billion, one hundred twenty-three million, twenty thousand, fifty-three".