33312113017 has 2 divisors, whose sum is σ = 33312113018. Its totient is φ = 33312113016.

The previous prime is 33312112991. The next prime is 33312113027. The reversal of 33312113017 is 71031121333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25755114256 + 7556998761 = 160484^2 + 86931^2 .

It is an emirp because it is prime and its reverse (71031121333) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-33312113017 is a prime.

It is a super-2 number, since 2×33312113017² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33312112982 and 33312113000.

It is not a weakly prime, because it can be changed into another prime (33312113027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16656056508 + 16656056509.

It is an arithmetic number, because the mean of its divisors is an integer number (16656056509).

Almost surely, 2^33312113017 is an apocalyptic number.

It is an amenable number.

33312113017 is a deficient number, since it is larger than the sum of its proper divisors (1).

33312113017 is an equidigital number, since it uses as much as digits as its factorization.

33312113017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1134, while the sum is 25.

The spelling of 33312113017 in words is "thirty-three billion, three hundred twelve million, one hundred thirteen thousand, seventeen".