Base | Representation |
---|---|
bin | 1100011010001110… |
… | …0100011101100001 |
3 | 22121011021011100221 |
4 | 3012203210131201 |
5 | 23310242310103 |
6 | 1310315243041 |
7 | 145356562462 |
oct | 30643443541 |
9 | 8534234327 |
10 | 3331213153 |
11 | 145a423824 |
12 | 78b749481 |
13 | 4111c0558 |
14 | 2385c2d69 |
15 | 1476bb1bd |
hex | c68e4761 |
3331213153 has 2 divisors, whose sum is σ = 3331213154. Its totient is φ = 3331213152.
The previous prime is 3331213079. The next prime is 3331213169. The reversal of 3331213153 is 3513121333.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2345755489 + 985457664 = 48433^2 + 31392^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3331213153 is a prime.
It is a super-2 number, since 2×33312131532 = 22193962141440402818, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3331213253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665606576 + 1665606577.
It is an arithmetic number, because the mean of its divisors is an integer number (1665606577).
Almost surely, 23331213153 is an apocalyptic number.
It is an amenable number.
3331213153 is a deficient number, since it is larger than the sum of its proper divisors (1).
3331213153 is an equidigital number, since it uses as much as digits as its factorization.
3331213153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2430, while the sum is 25.
The square root of 3331213153 is about 57716.6626980459. The cubic root of 3331213153 is about 1493.4848021395.
Adding to 3331213153 its reverse (3513121333), we get a palindrome (6844334486).
The spelling of 3331213153 in words is "three billion, three hundred thirty-one million, two hundred thirteen thousand, one hundred fifty-three".
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