Base | Representation |
---|---|
bin | 110000011110100000111… |
… | …101000000010101001101 |
3 | 102210110200000200002211021 |
4 | 300132200331000111031 |
5 | 414040000300013401 |
6 | 11030213400154141 |
7 | 462451501542112 |
oct | 60364075002515 |
9 | 12713600602737 |
10 | 3331300001101 |
11 | 1074884005086 |
12 | 459765768951 |
13 | 1b21a915c207 |
14 | b7342da4909 |
15 | 5b9c4c1c2a1 |
hex | 307a0f4054d |
3331300001101 has 2 divisors, whose sum is σ = 3331300001102. Its totient is φ = 3331300001100.
The previous prime is 3331300001059. The next prime is 3331300001119. The reversal of 3331300001101 is 1011000031333.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3187546036900 + 143753964201 = 1785370^2 + 379149^2 .
It is a cyclic number.
It is not a de Polignac number, because 3331300001101 - 217 = 3331299870029 is a prime.
It is a super-2 number, since 2×33313000011012 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3331300001801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665650000550 + 1665650000551.
It is an arithmetic number, because the mean of its divisors is an integer number (1665650000551).
Almost surely, 23331300001101 is an apocalyptic number.
It is an amenable number.
3331300001101 is a deficient number, since it is larger than the sum of its proper divisors (1).
3331300001101 is an equidigital number, since it uses as much as digits as its factorization.
3331300001101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 3331300001101 its reverse (1011000031333), we get a palindrome (4342300032434).
The spelling of 3331300001101 in words is "three trillion, three hundred thirty-one billion, three hundred million, one thousand, one hundred one".
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