Base | Representation |
---|---|
bin | 110000011110100001100… |
… | …111011000011111001101 |
3 | 102210110200210120111111102 |
4 | 300132201213120133031 |
5 | 414040011121010333 |
6 | 11030214434232445 |
7 | 462451665140621 |
oct | 60364147303715 |
9 | 12713623514442 |
10 | 3331311110093 |
11 | 107488a30246a |
12 | 459769425725 |
13 | 1b21ab54b795 |
14 | b7344657181 |
15 | 5b9c5bb3ae8 |
hex | 307a19d87cd |
3331311110093 has 2 divisors, whose sum is σ = 3331311110094. Its totient is φ = 3331311110092.
The previous prime is 3331311110047. The next prime is 3331311110159. The reversal of 3331311110093 is 3900111131333.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2867935476004 + 463375634089 = 1693498^2 + 680717^2 .
It is a cyclic number.
It is not a de Polignac number, because 3331311110093 - 214 = 3331311093709 is a prime.
It is a super-2 number, since 2×33313111100932 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3331311110893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665655555046 + 1665655555047.
It is an arithmetic number, because the mean of its divisors is an integer number (1665655555047).
Almost surely, 23331311110093 is an apocalyptic number.
It is an amenable number.
3331311110093 is a deficient number, since it is larger than the sum of its proper divisors (1).
3331311110093 is an equidigital number, since it uses as much as digits as its factorization.
3331311110093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2187, while the sum is 29.
The spelling of 3331311110093 in words is "three trillion, three hundred thirty-one billion, three hundred eleven million, one hundred ten thousand, ninety-three".
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