3331400521 has 2 divisors, whose sum is σ = 3331400522. Its totient is φ = 3331400520.

The previous prime is 3331400519. The next prime is 3331400531. The reversal of 3331400521 is 1250041333.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3299353600 + 32046921 = 57440^2 + 5661^2 .

It is a cyclic number.

It is not a de Polignac number, because 3331400521 - 2¹ = 3331400519 is a prime.

It is a super-2 number, since 2×3331400521² = 22196458862638142882, which contains 22 as substring.

Together with 3331400519, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 3331400492 and 3331400501.

It is not a weakly prime, because it can be changed into another prime (3331400531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665700260 + 1665700261.

It is an arithmetic number, because the mean of its divisors is an integer number (1665700261).

Almost surely, 2^3331400521 is an apocalyptic number.

It is an amenable number.

3331400521 is a deficient number, since it is larger than the sum of its proper divisors (1).

3331400521 is an equidigital number, since it uses as much as digits as its factorization.

3331400521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 22.

The square root of 3331400521 is about 57718.2858459951. The cubic root of 3331400521 is about 1493.5128025507.

Adding to 3331400521 its reverse (1250041333), we get a palindrome (4581441854).

The spelling of 3331400521 in words is "three billion, three hundred thirty-one million, four hundred thousand, five hundred twenty-one".