Base | Representation |
---|---|
bin | 11111000010010001… |
… | …100011000101100101 |
3 | 10012000102021021111001 |
4 | 133002101203011211 |
5 | 1021221440314031 |
6 | 23150420113301 |
7 | 2256542416411 |
oct | 370221430545 |
9 | 105012237431 |
10 | 33324151141 |
11 | 13150683a86 |
12 | 6560235831 |
13 | 31b0c82138 |
14 | 1881b0dd41 |
15 | d0089c861 |
hex | 7c2463165 |
33324151141 has 2 divisors, whose sum is σ = 33324151142. Its totient is φ = 33324151140.
The previous prime is 33324151109. The next prime is 33324151153. The reversal of 33324151141 is 14115142333.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32880206241 + 443944900 = 181329^2 + 21070^2 .
It is an emirp because it is prime and its reverse (14115142333) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 33324151141 - 25 = 33324151109 is a prime.
It is a super-2 number, since 2×333241511412 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33324155141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16662075570 + 16662075571.
It is an arithmetic number, because the mean of its divisors is an integer number (16662075571).
Almost surely, 233324151141 is an apocalyptic number.
It is an amenable number.
33324151141 is a deficient number, since it is larger than the sum of its proper divisors (1).
33324151141 is an equidigital number, since it uses as much as digits as its factorization.
33324151141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4320, while the sum is 28.
Adding to 33324151141 its reverse (14115142333), we get a palindrome (47439293474).
The spelling of 33324151141 in words is "thirty-three billion, three hundred twenty-four million, one hundred fifty-one thousand, one hundred forty-one".
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