Base | Representation |
---|---|
bin | 1111001001110111001010… |
… | …01110110000101001100000 |
3 | 11100222202120221110212020211 |
4 | 13210323211032300221200 |
5 | 13331440431221242422 |
6 | 154512532131343504 |
7 | 10006410536332501 |
oct | 744734516605140 |
9 | 140882527425224 |
10 | 33324202134112 |
11 | a68879538765a |
12 | 38a2553a51b94 |
13 | 15795c6c1a866 |
14 | 832c857daba8 |
15 | 3cbc8b7e9577 |
hex | 1e4ee53b0a60 |
33324202134112 has 48 divisors (see below), whose sum is σ = 65638232906400. Its totient is φ = 16654176460800.
The previous prime is 33324202134089. The next prime is 33324202134133. The reversal of 33324202134112 is 21143120242333.
It is a super-2 number, since 2×333242021341122 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 771354112 + ... + 771397312.
It is an arithmetic number, because the mean of its divisors is an integer number (1367463185550).
Almost surely, 233324202134112 is an apocalyptic number.
33324202134112 is a gapful number since it is divisible by the number (32) formed by its first and last digit.
It is an amenable number.
33324202134112 is a deficient number, since it is larger than the sum of its proper divisors (32314030772288).
33324202134112 is a wasteful number, since it uses less digits than its factorization.
33324202134112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54119 (or 54111 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 33324202134112 its reverse (21143120242333), we get a palindrome (54467322376445).
The spelling of 33324202134112 in words is "thirty-three trillion, three hundred twenty-four billion, two hundred two million, one hundred thirty-four thousand, one hundred twelve".
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