Base | Representation |
---|---|
bin | 1100011010100010… |
… | …1000101011001101 |
3 | 22121020202122000101 |
4 | 3012220220223031 |
5 | 23311112304013 |
6 | 1310403531101 |
7 | 145404063235 |
oct | 30650505315 |
9 | 8536678011 |
10 | 3332541133 |
11 | 1460150529 |
12 | 790089a91 |
13 | 411566b3c |
14 | 23884acc5 |
15 | 14787e8dd |
hex | c6a28acd |
3332541133 has 2 divisors, whose sum is σ = 3332541134. Its totient is φ = 3332541132.
The previous prime is 3332541089. The next prime is 3332541143. The reversal of 3332541133 is 3311452333.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3197563209 + 134977924 = 56547^2 + 11618^2 .
It is a cyclic number.
It is not a de Polignac number, because 3332541133 - 29 = 3332540621 is a prime.
It is a super-2 number, since 2×33325411332 = 22211660806273847378, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3332541143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1666270566 + 1666270567.
It is an arithmetic number, because the mean of its divisors is an integer number (1666270567).
Almost surely, 23332541133 is an apocalyptic number.
It is an amenable number.
3332541133 is a deficient number, since it is larger than the sum of its proper divisors (1).
3332541133 is an equidigital number, since it uses as much as digits as its factorization.
3332541133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9720, while the sum is 28.
The square root of 3332541133 is about 57728.1658551525. The cubic root of 3332541133 is about 1493.6832337985.
Adding to 3332541133 its reverse (3311452333), we get a palindrome (6643993466).
The spelling of 3332541133 in words is "three billion, three hundred thirty-two million, five hundred forty-one thousand, one hundred thirty-three".
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