Base | Representation |
---|---|
bin | 1100011010111110… |
… | …0100111111111001 |
3 | 22121101012002111212 |
4 | 3012233210333321 |
5 | 23312044023311 |
6 | 1310510532505 |
7 | 145425413222 |
oct | 30657447771 |
9 | 8541162455 |
10 | 3334361081 |
11 | 1461183917 |
12 | 790807135 |
13 | 411a5332c |
14 | 238ba2249 |
15 | 147addc8b |
hex | c6be4ff9 |
3334361081 has 2 divisors, whose sum is σ = 3334361082. Its totient is φ = 3334361080.
The previous prime is 3334361047. The next prime is 3334361087. The reversal of 3334361081 is 1801634333.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2802643600 + 531717481 = 52940^2 + 23059^2 .
It is an emirp because it is prime and its reverse (1801634333) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3334361081 - 214 = 3334344697 is a prime.
It is a super-2 number, since 2×33343610812 = 22235927636974977122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3334361087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1667180540 + 1667180541.
It is an arithmetic number, because the mean of its divisors is an integer number (1667180541).
Almost surely, 23334361081 is an apocalyptic number.
It is an amenable number.
3334361081 is a deficient number, since it is larger than the sum of its proper divisors (1).
3334361081 is an equidigital number, since it uses as much as digits as its factorization.
3334361081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 32.
The square root of 3334361081 is about 57743.9267888840. The cubic root of 3334361081 is about 1493.9550915190.
The spelling of 3334361081 in words is "three billion, three hundred thirty-four million, three hundred sixty-one thousand, eighty-one".
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