Base | Representation |
---|---|
bin | 1100011010111110… |
… | …1110110101111111 |
3 | 22121101021010211102 |
4 | 3012233232311333 |
5 | 23312101321112 |
6 | 1310511443315 |
7 | 145425641621 |
oct | 30657566577 |
9 | 8541233742 |
10 | 3334401407 |
11 | 1461201147 |
12 | 79082653b |
13 | 411a687ac |
14 | 238bb2c11 |
15 | 147aeabc2 |
hex | c6beed7f |
3334401407 has 2 divisors, whose sum is σ = 3334401408. Its totient is φ = 3334401406.
The previous prime is 3334401397. The next prime is 3334401431. The reversal of 3334401407 is 7041044333.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3334401407 - 24 = 3334401391 is a prime.
It is a super-2 number, since 2×33344014072 = 22236465486007159298, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 3334401407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3334401457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1667200703 + 1667200704.
It is an arithmetic number, because the mean of its divisors is an integer number (1667200704).
Almost surely, 23334401407 is an apocalyptic number.
3334401407 is a deficient number, since it is larger than the sum of its proper divisors (1).
3334401407 is an equidigital number, since it uses as much as digits as its factorization.
3334401407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 29.
The square root of 3334401407 is about 57744.2759674065. The cubic root of 3334401407 is about 1493.9611141611.
The spelling of 3334401407 in words is "three billion, three hundred thirty-four million, four hundred one thousand, four hundred seven".
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