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3335423149 is a prime number
BaseRepresentation
bin1100011011001110…
…1000010010101101
322121110012001101201
43012303220102231
523312332020044
61310545405501
7145440425512
oct30663502255
98543161351
103335423149
111461839863
12791039891
13412035886
14238d9b309
15147c4d7d4
hexc6ce84ad

3335423149 has 2 divisors, whose sum is σ = 3335423150. Its totient is φ = 3335423148.

The previous prime is 3335423129. The next prime is 3335423159. The reversal of 3335423149 is 9413245333.

3335423149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3015657225 + 319765924 = 54915^2 + 17882^2 .

It is a cyclic number.

It is not a de Polignac number, because 3335423149 - 215 = 3335390381 is a prime.

It is a super-3 number, since 3×33354231493 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3335423129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1667711574 + 1667711575.

It is an arithmetic number, because the mean of its divisors is an integer number (1667711575).

Almost surely, 23335423149 is an apocalyptic number.

It is an amenable number.

3335423149 is a deficient number, since it is larger than the sum of its proper divisors (1).

3335423149 is an equidigital number, since it uses as much as digits as its factorization.

3335423149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 116640, while the sum is 37.

The square root of 3335423149 is about 57753.1224177533. The cubic root of 3335423149 is about 1494.1136939641.

The spelling of 3335423149 in words is "three billion, three hundred thirty-five million, four hundred twenty-three thousand, one hundred forty-nine".