334000111 has 2 divisors, whose sum is σ = 334000112. Its totient is φ = 334000110.

The previous prime is 334000103. The next prime is 334000123. The reversal of 334000111 is 111000433.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 334000111 - 2³ = 334000103 is a prime.

It is a super-2 number, since 2×334000111² = 223112148296024642, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 334000091 and 334000100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (334000171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167000055 + 167000056.

It is an arithmetic number, because the mean of its divisors is an integer number (167000056).

Almost surely, 2^334000111 is an apocalyptic number.

334000111 is a deficient number, since it is larger than the sum of its proper divisors (1).

334000111 is an equidigital number, since it uses as much as digits as its factorization.

334000111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 334000111 is about 18275.6699193217. The cubic root of 334000111 is about 693.8232842422.

Adding to 334000111 its reverse (111000433), we get a palindrome (445000544).

The spelling of 334000111 in words is "three hundred thirty-four million, one hundred eleven", and thus it is an aban number.