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334005121551 = 34092665557
BaseRepresentation
bin1001101110001000100…
…00011011001000001111
31011221010101120012000110
410313010100123020033
520433020302342201
6413235000531103
733062646455403
oct4670420331017
91157111505013
10334005121551
11119718202442
1254895780a93
132565bbb95ca
1412247475103
158a4cc206d6
hex4dc441b20f

334005121551 has 12 divisors (see below), whose sum is σ = 446432346312. Its totient is φ = 222125321664.

The previous prime is 334005121519. The next prime is 334005121579. The reversal of 334005121551 is 155121500433.

It is not a de Polignac number, because 334005121551 - 25 = 334005121519 is a prime.

It is a super-2 number, since 2×3340051215512 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (334005121451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 169065 + ... + 834621.

It is an arithmetic number, because the mean of its divisors is an integer number (37202695526).

Almost surely, 2334005121551 is an apocalyptic number.

334005121551 is a deficient number, since it is larger than the sum of its proper divisors (112427224761).

334005121551 is an frugal number, since it uses more digits than its factorization.

334005121551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 666378 (or 665969 counting only the distinct ones).

The product of its (nonzero) digits is 9000, while the sum is 30.

Adding to 334005121551 its reverse (155121500433), we get a palindrome (489126621984).

The spelling of 334005121551 in words is "three hundred thirty-four billion, five million, one hundred twenty-one thousand, five hundred fifty-one".

Divisors: 1 3 409 1227 167281 501843 665557 1996671 272212813 816638439 111335040517 334005121551