Base | Representation |
---|---|
bin | 11111000110110110… |
… | …110111110010011001 |
3 | 10012012202221211211012 |
4 | 133012312313302121 |
5 | 1021401131402441 |
6 | 23202204143305 |
7 | 2261465122244 |
oct | 370666676231 |
9 | 105182854735 |
10 | 33401044121 |
11 | 131900228a5 |
12 | 6581b37b35 |
13 | 31c3b95243 |
14 | 188c00825b |
15 | d074da9eb |
hex | 7c6db7c99 |
33401044121 has 2 divisors, whose sum is σ = 33401044122. Its totient is φ = 33401044120.
The previous prime is 33401044109. The next prime is 33401044123. The reversal of 33401044121 is 12144010433.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32919022096 + 482022025 = 181436^2 + 21955^2 .
It is a cyclic number.
It is not a de Polignac number, because 33401044121 - 222 = 33396849817 is a prime.
It is a super-2 number, since 2×334010441212 (a number of 22 digits) contains 22 as substring.
Together with 33401044123, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (33401044123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16700522060 + 16700522061.
It is an arithmetic number, because the mean of its divisors is an integer number (16700522061).
Almost surely, 233401044121 is an apocalyptic number.
It is an amenable number.
33401044121 is a deficient number, since it is larger than the sum of its proper divisors (1).
33401044121 is an equidigital number, since it uses as much as digits as its factorization.
33401044121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 33401044121 its reverse (12144010433), we get a palindrome (45545054554).
The spelling of 33401044121 in words is "thirty-three billion, four hundred one million, forty-four thousand, one hundred twenty-one".
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