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3340111333409 is a prime number
BaseRepresentation
bin110000100110101110001…
…001100100100000100001
3102211022102002202011102022
4300212232021210200201
5414211022000132114
611034232001431225
7463213033614434
oct60465611444041
912738362664368
103340111333409
1110785958534a4
1245b40463b515
131b2c817c2306
14b793b30781b
155bd3d57c48e
hex309ae264821

3340111333409 has 2 divisors, whose sum is σ = 3340111333410. Its totient is φ = 3340111333408.

The previous prime is 3340111333393. The next prime is 3340111333411. The reversal of 3340111333409 is 9043331110433.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2929050833809 + 411060499600 = 1711447^2 + 641140^2 .

It is an emirp because it is prime and its reverse (9043331110433) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3340111333409 - 24 = 3340111333393 is a prime.

It is a super-2 number, since 2×33401113334092 (a number of 26 digits) contains 22 as substring.

Together with 3340111333411, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3340111333499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670055666704 + 1670055666705.

It is an arithmetic number, because the mean of its divisors is an integer number (1670055666705).

Almost surely, 23340111333409 is an apocalyptic number.

It is an amenable number.

3340111333409 is a deficient number, since it is larger than the sum of its proper divisors (1).

3340111333409 is an equidigital number, since it uses as much as digits as its factorization.

3340111333409 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34992, while the sum is 35.

The spelling of 3340111333409 in words is "three trillion, three hundred forty billion, one hundred eleven million, three hundred thirty-three thousand, four hundred nine".