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33402301114141 is a prime number
BaseRepresentation
bin1111001100001000101000…
…10010101110011100011101
311101021020011210111010002201
413212010110102232130131
513334230403041123031
6155012445535451501
710015144105606021
oct746042422563435
9141236153433081
1033402301114141
11a708922201253
1238b570b086b91
131583a9225278b
14836973cc4381
153cdd0ce57d61
hex1e61144ae71d

33402301114141 has 2 divisors, whose sum is σ = 33402301114142. Its totient is φ = 33402301114140.

The previous prime is 33402301114121. The next prime is 33402301114159. The reversal of 33402301114141 is 14141110320433.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20735464211641 + 12666836902500 = 4553621^2 + 3559050^2 .

It is a cyclic number.

It is not a de Polignac number, because 33402301114141 - 235 = 33367941375773 is a prime.

It is a super-2 number, since 2×334023011141412 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33402301114121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16701150557070 + 16701150557071.

It is an arithmetic number, because the mean of its divisors is an integer number (16701150557071).

Almost surely, 233402301114141 is an apocalyptic number.

It is an amenable number.

33402301114141 is a deficient number, since it is larger than the sum of its proper divisors (1).

33402301114141 is an equidigital number, since it uses as much as digits as its factorization.

33402301114141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 33402301114141 its reverse (14141110320433), we get a palindrome (47543411434574).

The spelling of 33402301114141 in words is "thirty-three trillion, four hundred two billion, three hundred one million, one hundred fourteen thousand, one hundred forty-one".