3340401331 has 2 divisors, whose sum is σ = 3340401332. Its totient is φ = 3340401330.

The previous prime is 3340401299. The next prime is 3340401341. The reversal of 3340401331 is 1331040433.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (1331040433) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3340401331 - 2⁵ = 3340401299 is a prime.

It is a super-2 number, since 2×3340401331² = 22316562104293143122, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3340401341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670200665 + 1670200666.

It is an arithmetic number, because the mean of its divisors is an integer number (1670200666).

Almost surely, 2^3340401331 is an apocalyptic number.

3340401331 is a deficient number, since it is larger than the sum of its proper divisors (1).

3340401331 is an equidigital number, since it uses as much as digits as its factorization.

3340401331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 22.

The square root of 3340401331 is about 57796.2051608927. The cubic root of 3340401331 is about 1494.8566554210.

Adding to 3340401331 its reverse (1331040433), we get a palindrome (4671441764).

The spelling of 3340401331 in words is "three billion, three hundred forty million, four hundred one thousand, three hundred thirty-one".