3340404251 has 2 divisors, whose sum is σ = 3340404252. Its totient is φ = 3340404250.

The previous prime is 3340404233. The next prime is 3340404253. The reversal of 3340404251 is 1524040433.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3340404251 is a prime.

It is a super-2 number, since 2×3340404251² = 22316601120197742002, which contains 22 as substring.

Together with 3340404253, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3340404251.

It is not a weakly prime, because it can be changed into another prime (3340404253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670202125 + 1670202126.

It is an arithmetic number, because the mean of its divisors is an integer number (1670202126).

Almost surely, 2^3340404251 is an apocalyptic number.

3340404251 is a deficient number, since it is larger than the sum of its proper divisors (1).

3340404251 is an equidigital number, since it uses as much as digits as its factorization.

3340404251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 26.

The square root of 3340404251 is about 57796.2304220613. The cubic root of 3340404251 is about 1494.8570909954.

Adding to 3340404251 its reverse (1524040433), we get a palindrome (4864444684).

The spelling of 3340404251 in words is "three billion, three hundred forty million, four hundred four thousand, two hundred fifty-one".