3340404283 has 2 divisors, whose sum is σ = 3340404284. Its totient is φ = 3340404282.

The previous prime is 3340404259. The next prime is 3340404311. The reversal of 3340404283 is 3824040433.

3340404283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3340404283 - 2⁵ = 3340404251 is a prime.

It is a super-2 number, since 2×3340404283² = 22316601547769488178, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3340404203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670202141 + 1670202142.

It is an arithmetic number, because the mean of its divisors is an integer number (1670202142).

Almost surely, 2^3340404283 is an apocalyptic number.

3340404283 is a deficient number, since it is larger than the sum of its proper divisors (1).

3340404283 is an equidigital number, since it uses as much as digits as its factorization.

3340404283 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 31.

The square root of 3340404283 is about 57796.2306988959. The cubic root of 3340404283 is about 1494.8570957688.

The spelling of 3340404283 in words is "three billion, three hundred forty million, four hundred four thousand, two hundred eighty-three".