Base | Representation |
---|---|
bin | 1001101110001101001… |
… | …01101010010110011001 |
3 | 1011221020010011210001002 |
4 | 10313012211222112121 |
5 | 20433110311241403 |
6 | 413242515234345 |
7 | 33063633135212 |
oct | 4670645522631 |
9 | 1157203153032 |
10 | 334044243353 |
11 | 1197382a3207 |
12 | 548a68a89b5 |
13 | 256670364c2 |
14 | 1224c73a409 |
15 | 8a5139c188 |
hex | 4dc696a599 |
334044243353 has 2 divisors, whose sum is σ = 334044243354. Its totient is φ = 334044243352.
The previous prime is 334044243331. The next prime is 334044243359. The reversal of 334044243353 is 353342440433.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 329203980169 + 4840263184 = 573763^2 + 69572^2 .
It is a cyclic number.
It is not a de Polignac number, because 334044243353 - 28 = 334044243097 is a prime.
It is a super-2 number, since 2×3340442433532 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (334044243359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167022121676 + 167022121677.
It is an arithmetic number, because the mean of its divisors is an integer number (167022121677).
Almost surely, 2334044243353 is an apocalyptic number.
It is an amenable number.
334044243353 is a deficient number, since it is larger than the sum of its proper divisors (1).
334044243353 is an equidigital number, since it uses as much as digits as its factorization.
334044243353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 622080, while the sum is 38.
Adding to 334044243353 its reverse (353342440433), we get a palindrome (687386683786).
The spelling of 334044243353 in words is "three hundred thirty-four billion, forty-four million, two hundred forty-three thousand, three hundred fifty-three".
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