Base | Representation |
---|---|
bin | 10011111010100… |
… | …010110101001111 |
3 | 212021200202102022 |
4 | 103322202311033 |
5 | 1141013123002 |
6 | 53053120355 |
7 | 11164631444 |
oct | 2372426517 |
9 | 767622368 |
10 | 334114127 |
11 | 161664986 |
12 | 93a890bb |
13 | 542b3589 |
14 | 325339cb |
15 | 1e4ebba2 |
hex | 13ea2d4f |
334114127 has 2 divisors, whose sum is σ = 334114128. Its totient is φ = 334114126.
The previous prime is 334114087. The next prime is 334114139. The reversal of 334114127 is 721411433.
It is a strong prime.
It is an emirp because it is prime and its reverse (721411433) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 334114127 - 210 = 334113103 is a prime.
It is a super-2 number, since 2×3341141272 = 223264499721944258, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 334114096 and 334114105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (334113127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167057063 + 167057064.
It is an arithmetic number, because the mean of its divisors is an integer number (167057064).
Almost surely, 2334114127 is an apocalyptic number.
334114127 is a deficient number, since it is larger than the sum of its proper divisors (1).
334114127 is an equidigital number, since it uses as much as digits as its factorization.
334114127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2016, while the sum is 26.
The square root of 334114127 is about 18278.7889916154. The cubic root of 334114127 is about 693.9022242917.
The spelling of 334114127 in words is "three hundred thirty-four million, one hundred fourteen thousand, one hundred twenty-seven".
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