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334114242144181 is a prime number
BaseRepresentation
bin100101111111000000000100…
…0101101111010011110110101
31121211000000021000002021110121
41023332000020231322132311
5322243111431442103211
63142333544111051541
7130242646250322232
oct11376001055723665
91554000230067417
10334114242144181
1197506066393a34
12315816b3810bb1
1311457ab797cb75
145c7130388c789
152896128d42271
hex12fe008b7a7b5

334114242144181 has 2 divisors, whose sum is σ = 334114242144182. Its totient is φ = 334114242144180.

The previous prime is 334114242144173. The next prime is 334114242144211. The reversal of 334114242144181 is 181441242411433.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 276508176246225 + 57606065897956 = 16628535^2 + 7589866^2 .

It is a cyclic number.

It is not a de Polignac number, because 334114242144181 - 23 = 334114242144173 is a prime.

It is a super-2 number, since 2×3341142421441812 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (334114242144281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167057121072090 + 167057121072091.

It is an arithmetic number, because the mean of its divisors is an integer number (167057121072091).

Almost surely, 2334114242144181 is an apocalyptic number.

It is an amenable number.

334114242144181 is a deficient number, since it is larger than the sum of its proper divisors (1).

334114242144181 is an equidigital number, since it uses as much as digits as its factorization.

334114242144181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 294912, while the sum is 43.

The spelling of 334114242144181 in words is "three hundred thirty-four trillion, one hundred fourteen billion, two hundred forty-two million, one hundred forty-four thousand, one hundred eighty-one".