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334121314333 is a prime number
BaseRepresentation
bin1001101110010110010…
…11101010100000011101
31011221102111012101112211
410313023023222200131
520433240024024313
6413254311200421
733065560212022
oct4671313524035
91157374171484
10334121314333
11119777853834
1254908676111
1325679cac631
1412258a7d549
158a58022e3d
hex4dcb2ea81d

334121314333 has 2 divisors, whose sum is σ = 334121314334. Its totient is φ = 334121314332.

The previous prime is 334121314297. The next prime is 334121314339. The reversal of 334121314333 is 333413121433.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 202408210404 + 131713103929 = 449898^2 + 362923^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-334121314333 is a prime.

It is a super-2 number, since 2×3341213143332 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 334121314295 and 334121314304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (334121314339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167060657166 + 167060657167.

It is an arithmetic number, because the mean of its divisors is an integer number (167060657167).

Almost surely, 2334121314333 is an apocalyptic number.

It is an amenable number.

334121314333 is a deficient number, since it is larger than the sum of its proper divisors (1).

334121314333 is an equidigital number, since it uses as much as digits as its factorization.

334121314333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 23328, while the sum is 31.

Adding to 334121314333 its reverse (333413121433), we get a palindrome (667534435766).

The spelling of 334121314333 in words is "three hundred thirty-four billion, one hundred twenty-one million, three hundred fourteen thousand, three hundred thirty-three".