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3341233544149 is a prime number
BaseRepresentation
bin110000100111110001000…
…010011101101111010101
3102211102022022101101011001
4300213301002131233111
5414220321241403044
611034535210343301
7463252611345034
oct60476102355725
912742268341131
103341233544149
111079011258a96
1245b67842ab31
131b310014b737
14b7a0638871b
155bda6d4e2d4
hex309f109dbd5

3341233544149 has 2 divisors, whose sum is σ = 3341233544150. Its totient is φ = 3341233544148.

The previous prime is 3341233544071. The next prime is 3341233544191. The reversal of 3341233544149 is 9414453321433.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3246778741924 + 94454802225 = 1801882^2 + 307335^2 .

It is a cyclic number.

It is not a de Polignac number, because 3341233544149 - 221 = 3341231446997 is a prime.

It is a super-2 number, since 2×33412335441492 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3341233544099 and 3341233544108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3341233542149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670616772074 + 1670616772075.

It is an arithmetic number, because the mean of its divisors is an integer number (1670616772075).

Almost surely, 23341233544149 is an apocalyptic number.

It is an amenable number.

3341233544149 is a deficient number, since it is larger than the sum of its proper divisors (1).

3341233544149 is an equidigital number, since it uses as much as digits as its factorization.

3341233544149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1866240, while the sum is 46.

The spelling of 3341233544149 in words is "three trillion, three hundred forty-one billion, two hundred thirty-three million, five hundred forty-four thousand, one hundred forty-nine".