Base | Representation |
---|---|
bin | 11111000111100100… |
… | …011111101111010001 |
3 | 10012020121110111000121 |
4 | 133013210133233101 |
5 | 1021412212113431 |
6 | 23203312350241 |
7 | 2262001564351 |
oct | 370744375721 |
9 | 105217414017 |
10 | 33413004241 |
11 | 131968516a1 |
12 | 6585b45381 |
13 | 31c64c2036 |
14 | 188d83cb61 |
15 | d0859e611 |
hex | 7c791fbd1 |
33413004241 has 2 divisors, whose sum is σ = 33413004242. Its totient is φ = 33413004240.
The previous prime is 33413004143. The next prime is 33413004277. The reversal of 33413004241 is 14240031433.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23014103616 + 10398900625 = 151704^2 + 101975^2 .
It is a cyclic number.
It is not a de Polignac number, because 33413004241 - 27 = 33413004113 is a prime.
It is a super-2 number, since 2×334130042412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (33413004041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16706502120 + 16706502121.
It is an arithmetic number, because the mean of its divisors is an integer number (16706502121).
Almost surely, 233413004241 is an apocalyptic number.
It is an amenable number.
33413004241 is a deficient number, since it is larger than the sum of its proper divisors (1).
33413004241 is an equidigital number, since it uses as much as digits as its factorization.
33413004241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 33413004241 its reverse (14240031433), we get a palindrome (47653035674).
The spelling of 33413004241 in words is "thirty-three billion, four hundred thirteen million, four thousand, two hundred forty-one".
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