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334134386077 is a prime number
BaseRepresentation
bin1001101110010111111…
…01100001110110011101
31011221110101210111121111
410313023331201312131
520433301400323302
6413255455302021
733066106264042
oct4671375416635
91157411714544
10334134386077
11119784171828
1254910b1a911
132567c9083ab
141225a6c31c9
158a592560d7
hex4dcbf61d9d

334134386077 has 2 divisors, whose sum is σ = 334134386078. Its totient is φ = 334134386076.

The previous prime is 334134386059. The next prime is 334134386111. The reversal of 334134386077 is 770683431433.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 301482257476 + 32652128601 = 549074^2 + 180699^2 .

It is an emirp because it is prime and its reverse (770683431433) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 334134386077 - 211 = 334134384029 is a prime.

It is a super-2 number, since 2×3341343860772 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 334134386077.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (334134386477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167067193038 + 167067193039.

It is an arithmetic number, because the mean of its divisors is an integer number (167067193039).

Almost surely, 2334134386077 is an apocalyptic number.

It is an amenable number.

334134386077 is a deficient number, since it is larger than the sum of its proper divisors (1).

334134386077 is an equidigital number, since it uses as much as digits as its factorization.

334134386077 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3048192, while the sum is 49.

The spelling of 334134386077 in words is "three hundred thirty-four billion, one hundred thirty-four million, three hundred eighty-six thousand, seventy-seven".