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3341424433 is a prime number
BaseRepresentation
bin1100011100101010…
…0001011100110001
322121212110221121111
43013022201130301
523320401040213
61311322153321
7145542432124
oct30712413461
98555427544
103341424433
1114651686a6
12793052841
13413357329
14239ac03bb
15148536a3d
hexc72a1731

3341424433 has 2 divisors, whose sum is σ = 3341424434. Its totient is φ = 3341424432.

The previous prime is 3341424431. The next prime is 3341424487. The reversal of 3341424433 is 3344241433.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2356908304 + 984516129 = 48548^2 + 31377^2 .

It is a cyclic number.

It is not a de Polignac number, because 3341424433 - 21 = 3341424431 is a prime.

It is a super-2 number, since 2×33414244332 = 22330234482898742978, which contains 22 as substring.

Together with 3341424431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 3341424395 and 3341424404.

It is not a weakly prime, because it can be changed into another prime (3341424431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670712216 + 1670712217.

It is an arithmetic number, because the mean of its divisors is an integer number (1670712217).

Almost surely, 23341424433 is an apocalyptic number.

It is an amenable number.

3341424433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3341424433 is an equidigital number, since it uses as much as digits as its factorization.

3341424433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 31.

The square root of 3341424433 is about 57805.0554277046. The cubic root of 3341424433 is about 1495.0092553202.

Adding to 3341424433 its reverse (3344241433), we get a palindrome (6685665866).

The spelling of 3341424433 in words is "three billion, three hundred forty-one million, four hundred twenty-four thousand, four hundred thirty-three".