Base | Representation |
---|---|
bin | 110000101000011111011… |
… | …111111001100010101101 |
3 | 102211111022122002110012221 |
4 | 300220133133321202231 |
5 | 414223420312342031 |
6 | 11035144413155341 |
7 | 463311124615336 |
oct | 60503737714255 |
9 | 12744278073187 |
10 | 3342013012141 |
11 | 1079381245911 |
12 | 45b85548bb51 |
13 | 1b31c5792cbb |
14 | b7a7bacb28d |
15 | 5be004bca11 |
hex | 30a1f7f98ad |
3342013012141 has 16 divisors (see below), whose sum is σ = 3411626803200. Its totient is φ = 3273103782000.
The previous prime is 3342013012109. The next prime is 3342013012147. The reversal of 3342013012141 is 1412103102433.
It is a cyclic number.
It is not a de Polignac number, because 3342013012141 - 25 = 3342013012109 is a prime.
It is a super-2 number, since 2×33420130121412 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3342013012147) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24261820 + ... + 24399178.
It is an arithmetic number, because the mean of its divisors is an integer number (213226675200).
Almost surely, 23342013012141 is an apocalyptic number.
It is an amenable number.
3342013012141 is a deficient number, since it is larger than the sum of its proper divisors (69613791059).
3342013012141 is a wasteful number, since it uses less digits than its factorization.
3342013012141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 139920.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 3342013012141 its reverse (1412103102433), we get a palindrome (4754116114574).
The spelling of 3342013012141 in words is "three trillion, three hundred forty-two billion, thirteen million, twelve thousand, one hundred forty-one".
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