Base | Representation |
---|---|
bin | 110000101001101000110… |
… | …101001100111100011011 |
3 | 102211121111101011020201002 |
4 | 300221220311030330123 |
5 | 414233430243132103 |
6 | 11035510443215215 |
7 | 463353454310651 |
oct | 60515065147433 |
9 | 12747441136632 |
10 | 3343243333403 |
11 | 1079952781446 |
12 | 45bb3951750b |
13 | 1b336064274c |
14 | b7b57270dd1 |
15 | 5be734e7488 |
hex | 30a68d4cf1b |
3343243333403 has 2 divisors, whose sum is σ = 3343243333404. Its totient is φ = 3343243333402.
The previous prime is 3343243333301. The next prime is 3343243333483. The reversal of 3343243333403 is 3043333423433.
3343243333403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3343243333403 - 222 = 3343239139099 is a prime.
It is a super-2 number, since 2×33432433334032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3343243333483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1671621666701 + 1671621666702.
It is an arithmetic number, because the mean of its divisors is an integer number (1671621666702).
Almost surely, 23343243333403 is an apocalyptic number.
3343243333403 is a deficient number, since it is larger than the sum of its proper divisors (1).
3343243333403 is an equidigital number, since it uses as much as digits as its factorization.
3343243333403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 839808, while the sum is 38.
Adding to 3343243333403 its reverse (3043333423433), we get a palindrome (6386576756836).
The spelling of 3343243333403 in words is "three trillion, three hundred forty-three billion, two hundred forty-three million, three hundred thirty-three thousand, four hundred three".
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