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334331014397 is a prime number
BaseRepresentation
bin1001101110101111010…
…11100110110011111101
31011221222002210020221212
410313113223212303331
520434202214430042
6413331201534205
733104014506332
oct4672753466375
91157862706855
10334331014397
11119875161576
1254966944365
13256b1581b03
1412278868989
158a6b646482
hex4dd7ae6cfd

334331014397 has 2 divisors, whose sum is σ = 334331014398. Its totient is φ = 334331014396.

The previous prime is 334331014393. The next prime is 334331014411. The reversal of 334331014397 is 793410133433.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 332039860441 + 2291153956 = 576229^2 + 47866^2 .

It is a cyclic number.

It is not a de Polignac number, because 334331014397 - 22 = 334331014393 is a prime.

It is a super-2 number, since 2×3343310143972 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (334331014393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167165507198 + 167165507199.

It is an arithmetic number, because the mean of its divisors is an integer number (167165507199).

Almost surely, 2334331014397 is an apocalyptic number.

It is an amenable number.

334331014397 is a deficient number, since it is larger than the sum of its proper divisors (1).

334331014397 is an equidigital number, since it uses as much as digits as its factorization.

334331014397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 244944, while the sum is 41.

The spelling of 334331014397 in words is "three hundred thirty-four billion, three hundred thirty-one million, fourteen thousand, three hundred ninety-seven".