33434010131 has 2 divisors, whose sum is σ = 33434010132. Its totient is φ = 33434010130.

The previous prime is 33434010097. The next prime is 33434010157. The reversal of 33434010131 is 13101043433.

It is a strong prime.

It is an emirp because it is prime and its reverse (13101043433) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33434010131 - 2²² = 33429815827 is a prime.

It is a super-2 number, since 2×33434010131² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 33434010097 and 33434010106.

It is not a weakly prime, because it can be changed into another prime (33434010331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16717005065 + 16717005066.

It is an arithmetic number, because the mean of its divisors is an integer number (16717005066).

Almost surely, 2^33434010131 is an apocalyptic number.

33434010131 is a deficient number, since it is larger than the sum of its proper divisors (1).

33434010131 is an equidigital number, since it uses as much as digits as its factorization.

33434010131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 33434010131 its reverse (13101043433), we get a palindrome (46535053564).

The spelling of 33434010131 in words is "thirty-three billion, four hundred thirty-four million, ten thousand, one hundred thirty-one".