13101043433 has 2 divisors, whose sum is σ = 13101043434. Its totient is φ = 13101043432.

The previous prime is 13101043369. The next prime is 13101043507. The reversal of 13101043433 is 33434010131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9091241104 + 4009802329 = 95348^2 + 63323^2 .

It is an emirp because it is prime and its reverse (33434010131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13101043433 - 2⁶ = 13101043369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13101043399 and 13101043408.

It is not a weakly prime, because it can be changed into another prime (13101043933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550521716 + 6550521717.

It is an arithmetic number, because the mean of its divisors is an integer number (6550521717).

Almost surely, 2^13101043433 is an apocalyptic number.

It is an amenable number.

13101043433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101043433 is an equidigital number, since it uses as much as digits as its factorization.

13101043433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13101043433 its reverse (33434010131), we get a palindrome (46535053564).

The spelling of 13101043433 in words is "thirteen billion, one hundred one million, forty-three thousand, four hundred thirty-three".