Base | Representation |
---|---|
bin | 1001101110110111111… |
… | …00000000101001101011 |
3 | 1011222011002011012200212 |
4 | 10313123330000221223 |
5 | 20434324010022103 |
6 | 413342232251335 |
7 | 33105542462006 |
oct | 4673374005153 |
9 | 1158132135625 |
10 | 334402423403 |
11 | 1199014a5184 |
12 | 54986840b4b |
13 | 256c32c4a69 |
14 | 1228413653d |
15 | 8a72a4e7d8 |
hex | 4ddbf00a6b |
334402423403 has 2 divisors, whose sum is σ = 334402423404. Its totient is φ = 334402423402.
The previous prime is 334402423361. The next prime is 334402423427. The reversal of 334402423403 is 304324204433.
It is a strong prime.
It is an emirp because it is prime and its reverse (304324204433) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 334402423403 - 224 = 334385646187 is a prime.
It is a super-2 number, since 2×3344024234032 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 334402423403.
It is not a weakly prime, because it can be changed into another prime (334402423493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167201211701 + 167201211702.
It is an arithmetic number, because the mean of its divisors is an integer number (167201211702).
Almost surely, 2334402423403 is an apocalyptic number.
334402423403 is a deficient number, since it is larger than the sum of its proper divisors (1).
334402423403 is an equidigital number, since it uses as much as digits as its factorization.
334402423403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 32.
Adding to 334402423403 its reverse (304324204433), we get a palindrome (638726627836).
The spelling of 334402423403 in words is "three hundred thirty-four billion, four hundred two million, four hundred twenty-three thousand, four hundred three".
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