Base | Representation |
---|---|
bin | 110000101010011101010… |
… | …100110101100001011111 |
3 | 102211200202202100211211111 |
4 | 300222131110311201133 |
5 | 414242231223310221 |
6 | 11040134104002451 |
7 | 463414340226334 |
oct | 60523524654137 |
9 | 12750682324744 |
10 | 3344124041311 |
11 | 107a264927319 |
12 | 460144460427 |
13 | 1b3470c42ca1 |
14 | b7bdc20898b |
15 | 5bec59b2be1 |
hex | 30a9d53585f |
3344124041311 has 2 divisors, whose sum is σ = 3344124041312. Its totient is φ = 3344124041310.
The previous prime is 3344124041303. The next prime is 3344124041333. The reversal of 3344124041311 is 1131404214433.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3344124041311 - 23 = 3344124041303 is a prime.
It is a super-2 number, since 2×33441240413112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3344124047311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1672062020655 + 1672062020656.
It is an arithmetic number, because the mean of its divisors is an integer number (1672062020656).
Almost surely, 23344124041311 is an apocalyptic number.
3344124041311 is a deficient number, since it is larger than the sum of its proper divisors (1).
3344124041311 is an equidigital number, since it uses as much as digits as its factorization.
3344124041311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 3344124041311 its reverse (1131404214433), we get a palindrome (4475528255744).
The spelling of 3344124041311 in words is "three trillion, three hundred forty-four billion, one hundred twenty-four million, forty-one thousand, three hundred eleven".
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