Base | Representation |
---|---|
bin | 1001110000001100011… |
… | …10110101001110010111 |
3 | 1012000222112100110100122 |
4 | 10320012032311032113 |
5 | 20442302133003112 |
6 | 413540501102155 |
7 | 33132250001432 |
oct | 4700616651627 |
9 | 1160875313318 |
10 | 335112000407 |
11 | 11a135a95958 |
12 | 54b443b795b |
13 | 257a7308302 |
14 | 12310484819 |
15 | 8ab4eb4872 |
hex | 4e063b5397 |
335112000407 has 2 divisors, whose sum is σ = 335112000408. Its totient is φ = 335112000406.
The previous prime is 335112000403. The next prime is 335112000437. The reversal of 335112000407 is 704000211533.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 335112000407 - 22 = 335112000403 is a prime.
It is a super-2 number, since 2×3351120004072 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (335112000403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167556000203 + 167556000204.
It is an arithmetic number, because the mean of its divisors is an integer number (167556000204).
Almost surely, 2335112000407 is an apocalyptic number.
335112000407 is a deficient number, since it is larger than the sum of its proper divisors (1).
335112000407 is an equidigital number, since it uses as much as digits as its factorization.
335112000407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 26.
The spelling of 335112000407 in words is "three hundred thirty-five billion, one hundred twelve million, four hundred seven", and thus it is an aban number.
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