33520013 has 2 divisors, whose sum is σ = 33520014. Its totient is φ = 33520012.

The previous prime is 33519979. The next prime is 33520031. The reversal of 33520013 is 31002533.

Together with next prime (33520031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29571844 + 3948169 = 5438^2 + 1987^2 .

It is an emirp because it is prime and its reverse (31002533) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33520013 - 2⁶ = 33519949 is a prime.

It is a super-2 number, since 2×33520013² = 2247182543040338, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 33519973 and 33520000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33520043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16760006 + 16760007.

It is an arithmetic number, because the mean of its divisors is an integer number (16760007).

Almost surely, 2^33520013 is an apocalyptic number.

It is an amenable number.

33520013 is a deficient number, since it is larger than the sum of its proper divisors (1).

33520013 is an equidigital number, since it uses as much as digits as its factorization.

33520013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 17.

The square root of 33520013 is about 5789.6470531458. The cubic root of 33520013 is about 322.4294675791.

Adding to 33520013 its reverse (31002533), we get a palindrome (64522546).

The spelling of 33520013 in words is "thirty-three million, five hundred twenty thousand, thirteen".