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3354020415113 is a prime number
BaseRepresentation
bin110000110011101011001…
…100100000011010001001
3102212122022110010201112112
4300303223030200122021
5414423013211240423
611044452105352105
7464214516064154
oct60635314403211
912778273121475
103354020415113
1110834830a3445
12462046798635
131b438a31a284
14b849a6b4c9b
155c3a4701a78
hex30ceb320689

3354020415113 has 2 divisors, whose sum is σ = 3354020415114. Its totient is φ = 3354020415112.

The previous prime is 3354020415037. The next prime is 3354020415121. The reversal of 3354020415113 is 3115140204533.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1776363836809 + 1577656578304 = 1332803^2 + 1256048^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3354020415113 is a prime.

It is a super-2 number, since 2×33540204151132 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3354020415113.

It is not a weakly prime, because it can be changed into another prime (3354020415413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1677010207556 + 1677010207557.

It is an arithmetic number, because the mean of its divisors is an integer number (1677010207557).

Almost surely, 23354020415113 is an apocalyptic number.

It is an amenable number.

3354020415113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3354020415113 is an equidigital number, since it uses as much as digits as its factorization.

3354020415113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 3354020415113 its reverse (3115140204533), we get a palindrome (6469160619646).

The spelling of 3354020415113 in words is "three trillion, three hundred fifty-four billion, twenty million, four hundred fifteen thousand, one hundred thirteen".