Base | Representation |
---|---|
bin | 110000110011110000101… |
… | …010010001010000101111 |
3 | 102212122112211122222022122 |
4 | 300303300222101100233 |
5 | 414423210144302341 |
6 | 11044505142503155 |
7 | 464220011321153 |
oct | 60636052212057 |
9 | 12778484588278 |
10 | 3354112103471 |
11 | 108351a928248 |
12 | 462071434abb |
13 | 1b43a331083c |
14 | b84a8941063 |
15 | 5c3ac7b394b |
hex | 30cf0a9142f |
3354112103471 has 2 divisors, whose sum is σ = 3354112103472. Its totient is φ = 3354112103470.
The previous prime is 3354112103413. The next prime is 3354112103513. The reversal of 3354112103471 is 1743012114533.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3354112103471 - 210 = 3354112102447 is a prime.
It is a super-3 number, since 3×33541121034713 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3354112103971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1677056051735 + 1677056051736.
It is an arithmetic number, because the mean of its divisors is an integer number (1677056051736).
Almost surely, 23354112103471 is an apocalyptic number.
3354112103471 is a deficient number, since it is larger than the sum of its proper divisors (1).
3354112103471 is an equidigital number, since it uses as much as digits as its factorization.
3354112103471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30240, while the sum is 35.
The spelling of 3354112103471 in words is "three trillion, three hundred fifty-four billion, one hundred twelve million, one hundred three thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •