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3365145061493 is a prime number
BaseRepresentation
bin110000111110000010010…
…001101010100001110101
3102220201000202010022110112
4300332002101222201311
5420113304113431433
611053532025232405
7465060301032425
oct60760221524165
912821022108415
103365145061493
111088171726976
12464230332705
131b5441007677
14b8c33d50485
155c8061b3348
hex30f8246a875

3365145061493 has 2 divisors, whose sum is σ = 3365145061494. Its totient is φ = 3365145061492.

The previous prime is 3365145061427. The next prime is 3365145061547. The reversal of 3365145061493 is 3941605415633.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2622916289764 + 742228771729 = 1619542^2 + 861527^2 .

It is a cyclic number.

It is not a de Polignac number, because 3365145061493 - 218 = 3365144799349 is a prime.

It is a super-2 number, since 2×33651450614932 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3365145061423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1682572530746 + 1682572530747.

It is an arithmetic number, because the mean of its divisors is an integer number (1682572530747).

Almost surely, 23365145061493 is an apocalyptic number.

It is an amenable number.

3365145061493 is a deficient number, since it is larger than the sum of its proper divisors (1).

3365145061493 is an equidigital number, since it uses as much as digits as its factorization.

3365145061493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3499200, while the sum is 50.

The spelling of 3365145061493 in words is "three trillion, three hundred sixty-five billion, one hundred forty-five million, sixty-one thousand, four hundred ninety-three".