Base | Representation |
---|---|
bin | 1100100110000011… |
… | …1000101000100001 |
3 | 22201121122111222002 |
4 | 3021200320220201 |
5 | 23410443402433 |
6 | 1315251053345 |
7 | 146531450165 |
oct | 31140705041 |
9 | 8647574862 |
10 | 3380840993 |
11 | 148543a972 |
12 | 7a42a1255 |
13 | 41b57843a |
14 | 241020ca5 |
15 | 14bc209e8 |
hex | c9838a21 |
3380840993 has 2 divisors, whose sum is σ = 3380840994. Its totient is φ = 3380840992.
The previous prime is 3380840891. The next prime is 3380841029. The reversal of 3380840993 is 3990480833.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2776025344 + 604815649 = 52688^2 + 24593^2 .
It is a cyclic number.
It is not a de Polignac number, because 3380840993 - 28 = 3380840737 is a prime.
It is a super-2 number, since 2×33808409932 = 22860171639898452098, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3380840093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1690420496 + 1690420497.
It is an arithmetic number, because the mean of its divisors is an integer number (1690420497).
Almost surely, 23380840993 is an apocalyptic number.
It is an amenable number.
3380840993 is a deficient number, since it is larger than the sum of its proper divisors (1).
3380840993 is an equidigital number, since it uses as much as digits as its factorization.
3380840993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 47.
The square root of 3380840993 is about 58144.9997248259. Note that the first 3 decimals coincide. The cubic root of 3380840993 is about 1500.8648335757.
It can be divided in two parts, 3380840 and 993, that added together give a palindrome (3381833).
The spelling of 3380840993 in words is "three billion, three hundred eighty million, eight hundred forty thousand, nine hundred ninety-three".
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