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3381205812013 is a prime number
BaseRepresentation
bin110001001100111111100…
…100100100001100101101
3102222020111001020222022101
4301030333210210030231
5420344202141441023
611105145435015101
7466166301124111
oct61147744441455
912866431228271
103381205812013
111093a63595507
12467372b9a491
131b6b00541343
14b9918db7741
155ce461a91ad
hex3133f92432d

3381205812013 has 2 divisors, whose sum is σ = 3381205812014. Its totient is φ = 3381205812012.

The previous prime is 3381205811957. The next prime is 3381205812059. The reversal of 3381205812013 is 3102185021833.

3381205812013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2375784484164 + 1005421327849 = 1541358^2 + 1002707^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3381205812013 is a prime.

It is a super-2 number, since 2×33812058120132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3381205812913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1690602906006 + 1690602906007.

It is an arithmetic number, because the mean of its divisors is an integer number (1690602906007).

Almost surely, 23381205812013 is an apocalyptic number.

It is an amenable number.

3381205812013 is a deficient number, since it is larger than the sum of its proper divisors (1).

3381205812013 is an equidigital number, since it uses as much as digits as its factorization.

3381205812013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 37.

The spelling of 3381205812013 in words is "three trillion, three hundred eighty-one billion, two hundred five million, eight hundred twelve thousand, thirteen".