Base | Representation |
---|---|
bin | 110001011110100110010… |
… | …110110110111011001101 |
3 | 110001001021112002101200011 |
4 | 301132212112312323031 |
5 | 421201411144004013 |
6 | 11121553344233221 |
7 | 500435620225216 |
oct | 61364626667315 |
9 | 13031245071604 |
10 | 3400110141133 |
11 | 10a0a84596802 |
12 | 46ab6a00b811 |
13 | 1b8823c228c4 |
14 | ba7cd96a40d |
15 | 5d6a0b46c3d |
hex | 317a65b6ecd |
3400110141133 has 2 divisors, whose sum is σ = 3400110141134. Its totient is φ = 3400110141132.
The previous prime is 3400110140969. The next prime is 3400110141139. The reversal of 3400110141133 is 3311410110043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1963187695044 + 1436922446089 = 1401138^2 + 1198717^2 .
It is a cyclic number.
It is not a de Polignac number, because 3400110141133 - 29 = 3400110140621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3400110141139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700055070566 + 1700055070567.
It is an arithmetic number, because the mean of its divisors is an integer number (1700055070567).
Almost surely, 23400110141133 is an apocalyptic number.
It is an amenable number.
3400110141133 is a deficient number, since it is larger than the sum of its proper divisors (1).
3400110141133 is an equidigital number, since it uses as much as digits as its factorization.
3400110141133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 3400110141133 its reverse (3311410110043), we get a palindrome (6711520251176).
The spelling of 3400110141133 in words is "three trillion, four hundred billion, one hundred ten million, one hundred forty-one thousand, one hundred thirty-three".
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