Base | Representation |
---|---|
bin | 110001011110110011000… |
… | …011001111000110110111 |
3 | 110001001211100210212211202 |
4 | 301132303003033012313 |
5 | 421202330203213421 |
6 | 11122030432523115 |
7 | 500444114320616 |
oct | 61366303170667 |
9 | 13031740725752 |
10 | 3400323101111 |
11 | 10a1083820792 |
12 | 46b0093b049b |
13 | 1b8859096b21 |
14 | ba80dd6387d |
15 | 5d6b46b110b |
hex | 317b30cf1b7 |
3400323101111 has 2 divisors, whose sum is σ = 3400323101112. Its totient is φ = 3400323101110.
The previous prime is 3400323101089. The next prime is 3400323101173. The reversal of 3400323101111 is 1111013230043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3400323101111 - 210 = 3400323100087 is a prime.
It is a super-4 number, since 4×34003231011114 (a number of 51 digits) contains 4444 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3400323101911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700161550555 + 1700161550556.
It is an arithmetic number, because the mean of its divisors is an integer number (1700161550556).
Almost surely, 23400323101111 is an apocalyptic number.
3400323101111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3400323101111 is an equidigital number, since it uses as much as digits as its factorization.
3400323101111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 3400323101111 its reverse (1111013230043), we get a palindrome (4511336331154).
The spelling of 3400323101111 in words is "three trillion, four hundred billion, three hundred twenty-three million, one hundred one thousand, one hundred eleven".
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