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34003440005401 is a prime number
BaseRepresentation
bin1111011101101000010101…
…11101100111000100011001
311110101200211012100211200201
413232310022331213010121
513424103021120133101
6200152544212302201
710106444641066516
oct756641275470431
9143350735324621
1034003440005401
11a91a861462699
123992117311961
1315c8683b29929
14857abd50c30d
153de792c8ee01
hex1eed0af67119

34003440005401 has 2 divisors, whose sum is σ = 34003440005402. Its totient is φ = 34003440005400.

The previous prime is 34003440005399. The next prime is 34003440005441. The reversal of 34003440005401 is 10450004430043.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33996129584400 + 7310421001 = 5830620^2 + 85501^2 .

It is a cyclic number.

It is not a de Polignac number, because 34003440005401 - 21 = 34003440005399 is a prime.

Together with 34003440005399, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 34003440005401.

It is not a weakly prime, because it can be changed into another prime (34003440005441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17001720002700 + 17001720002701.

It is an arithmetic number, because the mean of its divisors is an integer number (17001720002701).

Almost surely, 234003440005401 is an apocalyptic number.

It is an amenable number.

34003440005401 is a deficient number, since it is larger than the sum of its proper divisors (1).

34003440005401 is an equidigital number, since it uses as much as digits as its factorization.

34003440005401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 28.

Adding to 34003440005401 its reverse (10450004430043), we get a palindrome (44453444435444).

The spelling of 34003440005401 in words is "thirty-four trillion, three billion, four hundred forty million, five thousand, four hundred one".