Base | Representation |
---|---|
bin | 1001111001010111010… |
… | …00101110010011110101 |
3 | 1012111200120220221222011 |
4 | 10330223220232103311 |
5 | 21032342313341432 |
6 | 420113143404221 |
7 | 33365241443506 |
oct | 4745350562365 |
9 | 1174616827864 |
10 | 340034512117 |
11 | 121231687853 |
12 | 55a98a53671 |
13 | 260b00a5b31 |
14 | 1265a134bad |
15 | 8ca2211847 |
hex | 4f2ba2e4f5 |
340034512117 has 2 divisors, whose sum is σ = 340034512118. Its totient is φ = 340034512116.
The previous prime is 340034512067. The next prime is 340034512141. The reversal of 340034512117 is 711215430043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 335317432356 + 4717079761 = 579066^2 + 68681^2 .
It is a cyclic number.
It is not a de Polignac number, because 340034512117 - 219 = 340033987829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (340034512817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170017256058 + 170017256059.
It is an arithmetic number, because the mean of its divisors is an integer number (170017256059).
Almost surely, 2340034512117 is an apocalyptic number.
It is an amenable number.
340034512117 is a deficient number, since it is larger than the sum of its proper divisors (1).
340034512117 is an equidigital number, since it uses as much as digits as its factorization.
340034512117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
The spelling of 340034512117 in words is "three hundred forty billion, thirty-four million, five hundred twelve thousand, one hundred seventeen".
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