Base | Representation |
---|---|
bin | 1001111001010111111… |
… | …11010101110100101011 |
3 | 1012111201000002012001021 |
4 | 10330223333111310223 |
5 | 21032400323104011 |
6 | 420113514433311 |
7 | 33365343026326 |
oct | 4745377256453 |
9 | 1174630065037 |
10 | 340040441131 |
11 | 121234a67366 |
12 | 55a9aa32837 |
13 | 260b13a0721 |
14 | 1265ac397bd |
15 | 8ca29d3471 |
hex | 4f2bfd5d2b |
340040441131 has 2 divisors, whose sum is σ = 340040441132. Its totient is φ = 340040441130.
The previous prime is 340040441093. The next prime is 340040441171. The reversal of 340040441131 is 131144040043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 340040441131 - 221 = 340038343979 is a prime.
It is a super-2 number, since 2×3400404411312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 340040441096 and 340040441105.
It is not a weakly prime, because it can be changed into another prime (340040441171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170020220565 + 170020220566.
It is an arithmetic number, because the mean of its divisors is an integer number (170020220566).
Almost surely, 2340040441131 is an apocalyptic number.
340040441131 is a deficient number, since it is larger than the sum of its proper divisors (1).
340040441131 is an equidigital number, since it uses as much as digits as its factorization.
340040441131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 340040441131 its reverse (131144040043), we get a palindrome (471184481174).
The spelling of 340040441131 in words is "three hundred forty billion, forty million, four hundred forty-one thousand, one hundred thirty-one".
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