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340040441131 is a prime number
BaseRepresentation
bin1001111001010111111…
…11010101110100101011
31012111201000002012001021
410330223333111310223
521032400323104011
6420113514433311
733365343026326
oct4745377256453
91174630065037
10340040441131
11121234a67366
1255a9aa32837
13260b13a0721
141265ac397bd
158ca29d3471
hex4f2bfd5d2b

340040441131 has 2 divisors, whose sum is σ = 340040441132. Its totient is φ = 340040441130.

The previous prime is 340040441093. The next prime is 340040441171. The reversal of 340040441131 is 131144040043.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 340040441131 - 221 = 340038343979 is a prime.

It is a super-2 number, since 2×3400404411312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 340040441096 and 340040441105.

It is not a weakly prime, because it can be changed into another prime (340040441171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170020220565 + 170020220566.

It is an arithmetic number, because the mean of its divisors is an integer number (170020220566).

Almost surely, 2340040441131 is an apocalyptic number.

340040441131 is a deficient number, since it is larger than the sum of its proper divisors (1).

340040441131 is an equidigital number, since it uses as much as digits as its factorization.

340040441131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 340040441131 its reverse (131144040043), we get a palindrome (471184481174).

The spelling of 340040441131 in words is "three hundred forty billion, forty million, four hundred forty-one thousand, one hundred thirty-one".