Base | Representation |
---|---|
bin | 110001011110111001000… |
… | …001000000101101110011 |
3 | 110001002002100010110212122 |
4 | 301132321001000231303 |
5 | 421203031313244141 |
6 | 11122044405544455 |
7 | 500446441065332 |
oct | 61367101005563 |
9 | 13032070113778 |
10 | 3400423181171 |
11 | 10a1125267385 |
12 | 46b036a1512b |
13 | 1b8873a37bb3 |
14 | ba81d375d19 |
15 | 5d6bd37e64b |
hex | 317b9040b73 |
3400423181171 has 2 divisors, whose sum is σ = 3400423181172. Its totient is φ = 3400423181170.
The previous prime is 3400423181161. The next prime is 3400423181173. The reversal of 3400423181171 is 1711813240043.
It is a strong prime.
It is an emirp because it is prime and its reverse (1711813240043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3400423181171 - 238 = 3125545274227 is a prime.
It is a super-2 number, since 2×34004231811712 (a number of 26 digits) contains 22 as substring.
Together with 3400423181173, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3400423181173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700211590585 + 1700211590586.
It is an arithmetic number, because the mean of its divisors is an integer number (1700211590586).
Almost surely, 23400423181171 is an apocalyptic number.
3400423181171 is a deficient number, since it is larger than the sum of its proper divisors (1).
3400423181171 is an equidigital number, since it uses as much as digits as its factorization.
3400423181171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
The spelling of 3400423181171 in words is "three trillion, four hundred billion, four hundred twenty-three million, one hundred eighty-one thousand, one hundred seventy-one".
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