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3400423181171 is a prime number
BaseRepresentation
bin110001011110111001000…
…001000000101101110011
3110001002002100010110212122
4301132321001000231303
5421203031313244141
611122044405544455
7500446441065332
oct61367101005563
913032070113778
103400423181171
1110a1125267385
1246b036a1512b
131b8873a37bb3
14ba81d375d19
155d6bd37e64b
hex317b9040b73

3400423181171 has 2 divisors, whose sum is σ = 3400423181172. Its totient is φ = 3400423181170.

The previous prime is 3400423181161. The next prime is 3400423181173. The reversal of 3400423181171 is 1711813240043.

It is a strong prime.

It is an emirp because it is prime and its reverse (1711813240043) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3400423181171 - 238 = 3125545274227 is a prime.

It is a super-2 number, since 2×34004231811712 (a number of 26 digits) contains 22 as substring.

Together with 3400423181173, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3400423181173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700211590585 + 1700211590586.

It is an arithmetic number, because the mean of its divisors is an integer number (1700211590586).

Almost surely, 23400423181171 is an apocalyptic number.

3400423181171 is a deficient number, since it is larger than the sum of its proper divisors (1).

3400423181171 is an equidigital number, since it uses as much as digits as its factorization.

3400423181171 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 35.

The spelling of 3400423181171 in words is "three trillion, four hundred billion, four hundred twenty-three million, one hundred eighty-one thousand, one hundred seventy-one".